the limit for a function when approaching a specific point on the function can have two different…

the limit for a function when approaching a specific point on the function can have two different values.\nselect one:\no true\no false\n\nfour cards are randomly drawn from a standard deck of 52 cards. answer the questions below:\nhow many 4 - card groups are possible?\nfind the probability of selecting 1 ace and 3 kings?\n\nwhich two fundamental concepts of calculus are inverses of each other? select the two correct answers.\nselect one or more:\n□ a. logarithms\n□ b. derivatives\n□ c. integrals\n□ d. exponents\n□ e. limits\n□ f. factors
Answer
Answer:
- False
-
- For the number of 4 - card groups: $C(52,4)=\frac{52!}{4!(52 - 4)!}=\frac{52\times51\times50\times49}{4\times3\times2\times1}=270725$
- For the probability of selecting 1 ace and 3 kings:
- There are 4 aces and 4 kings in a deck. The number of ways to choose 1 ace out of 4 is $C(4,1)=\frac{4!}{1!(4 - 1)!}=4$. The number of ways to choose 3 kings out of 4 is $C(4,3)=\frac{4!}{3!(4 - 3)!}=4$. The number of favorable cases is $C(4,1)\times C(4,3)=4\times4 = 16$. The probability $P=\frac{16}{270725}$
- b. Derivatives, c. Integrals
Explanation:
Step1: Recall limit definition
The limit of a function $y = f(x)$ as $x$ approaches $a$, $\lim_{x\rightarrow a}f(x)$ has a unique value (if it exists). So the statement is false. 2.
Step1: Use combination formula for 4 - card groups
The formula for combinations is $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n = 52$ and $r = 4$.
Step2: Calculate favorable and total cases for ace - king selection
Find number of ways to choose aces and kings separately using combination formula and then find probability as $\frac{\text{Number of favorable cases}}{\text{Total number of cases}}$. 3.
Step1: Recall fundamental calculus concepts
The fundamental theorem of calculus states that differentiation and integration are inverse operations of each other.