line ab passes through points a(-6, 6) and b(12, 3). if the equation of the line is written in slope…
line ab passes through points a(-6, 6) and b(12, 3). if the equation of the line is written in slope - intercept form, y = mx + b, then m = -\\frac{1}{6}. what is the value of b?\n-6\n-5\n5\n6
Answer
Explanation:
Step1: Substitute point and slope into equation
We know the slope - intercept form $y = mx + b$, with $m=-\frac{1}{6}$, and we can use the point $A(-6,6)$. Substitute $x=-6$, $y = 6$ and $m=-\frac{1}{6}$ into the equation: $6=-\frac{1}{6}\times(-6)+b$.
Step2: Simplify the right - hand side
First, calculate $-\frac{1}{6}\times(-6)=1$. So the equation becomes $6 = 1 + b$.
Step3: Solve for b
Subtract 1 from both sides of the equation: $b=6 - 1$.
Answer:
5