line $jk$ passes through points $j(-4, -5)$ and $k(-6, 3)$. if the equation of the line is written in slope…

line $jk$ passes through points $j(-4, -5)$ and $k(-6, 3)$. if the equation of the line is written in slope - intercept form, $y = mx + b$, what is the value of $b$?\n-21\n-4\n11\n27

line $jk$ passes through points $j(-4, -5)$ and $k(-6, 3)$. if the equation of the line is written in slope - intercept form, $y = mx + b$, what is the value of $b$?\n-21\n-4\n11\n27

Answer

Answer:

A. -21

Explanation:

Step1: Calculate the slope $m$

$m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{3-(-5)}{-6 - (-4)}=\frac{3 + 5}{-6+4}=\frac{8}{-2}=-4$

Step2: Substitute a point and $m$ into $y=mx + b$

Using point $J(-4,-5)$ and $m = - 4$, we have $-5=-4\times(-4)+b$.

Step3: Solve for $b$

$-5 = 16 + b$, then $b=-5 - 16=-21$.