a line has a slope of -3 and passes through the point (6, -18). write its equation in slope-intercept form…

a line has a slope of -3 and passes through the point (6, -18). write its equation in slope-intercept form. write your answer using integers, proper fractions, and improper fractions in simplest form.

a line has a slope of -3 and passes through the point (6, -18). write its equation in slope-intercept form. write your answer using integers, proper fractions, and improper fractions in simplest form.

Answer

Explanation:

Step1: Recall the slope - intercept form

The slope - intercept form of a line is (y = mx + b), where (m) is the slope and (b) is the (y) - intercept. Given (m=-3), the equation becomes (y=-3x + b).

Step2: Substitute the point ((6,-18)) into the equation

Substitute (x = 6) and (y=-18) into (y=-3x + b). So, (-18=-3\times6 + b).

Step3: Solve for (b)

First, calculate (-3\times6=-18). Then the equation (-18=-18 + b) simplifies to (b = 0) (by adding (18) to both sides: (-18+18=-18 + 18+b)).

Answer:

(y=-3x)