which linear function represents the line given by the point - slope equation $y + 1=-3(x…

which linear function represents the line given by the point - slope equation $y + 1=-3(x - 5)$?\n$\\bigcirc$ $f(x)=-3x - 6$\n$\\bigcirc$ $f(x)=-3x - 4$\n$\\bigcirc$ $f(x)=-3x + 16$\n$\\bigcirc$ $f(x)=-3x + 14$

which linear function represents the line given by the point - slope equation $y + 1=-3(x - 5)$?\n$\\bigcirc$ $f(x)=-3x - 6$\n$\\bigcirc$ $f(x)=-3x - 4$\n$\\bigcirc$ $f(x)=-3x + 16$\n$\\bigcirc$ $f(x)=-3x + 14$

Answer

Explanation:

Step1: Expand the point - slope form

We start with the point - slope equation (y + 1=-3(x - 5)). Using the distributive property (a(b - c)=ab - ac), where (a=-3), (b = x) and (c = 5), we get (y+1=-3x+15).

Step2: Solve for y (or f(x))

Subtract 1 from both sides of the equation (y + 1=-3x+15). So (y=-3x + 15-1). Simplifying the right - hand side, we have (y=-3x+14). Since (y = f(x)) for a linear function, (f(x)=-3x + 14).

Answer:

(f(x)=-3x + 14) (the fourth option: (f(x)=-3x + 14))