which linear inequality is represented by the graph?\n$yleq\\frac{1}{3}x - 1.3$\n$yleq\\frac{1}{3}x-\\frac{4}…

which linear inequality is represented by the graph?\n$yleq\\frac{1}{3}x - 1.3$\n$yleq\\frac{1}{3}x-\\frac{4}{3}$\n$ygeq\\frac{1}{3}x - \\frac{4}{3}$\n$ygeq\\frac{1}{3}x - 1.3$
Answer
Explanation:
Step1: Identify the slope - intercept form
The equation of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.
Step2: Find the slope
The line passes through points $(0, - 1.3)$ and $(3,-0.3)$. The slope $m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{-0.3-(-1.3)}{3 - 0}=\frac{-0.3 + 1.3}{3}=\frac{1}{3}$.
Step3: Find the y - intercept
The line intersects the y - axis at the point $(0,-1.3)$, so $b=-1.3$.
Step4: Determine the inequality
The line is solid and the shaded region is below the line, so the inequality is $y\leq\frac{1}{3}x - 1.3$.
Answer:
$y\leq\frac{1}{3}x - 1.3$