what is $log_{5}(4 cdot 7) + log_{5}2$ written as a single log?$log_{5}21$$log_{5}30$$log_{5}56$$log_{5}26$
what is $log_{5}(4 cdot 7) + log_{5}2$ written as a single log?$log_{5}21$$log_{5}30$$log_{5}56$$log_{5}26$
Answer
Explanation:
Step1: Simplify the product inside log
$\log_{5}(4 \cdot 7) = \log_{5}28$
Step2: Apply log product rule
$\log_{5}28 + \log_{5}2 = \log_{5}(28 \cdot 2)$
Step3: Calculate the product
$\log_{5}(28 \cdot 2) = \log_{5}56$
Answer:
$\boldsymbol{\log_{5} 56}$