how long is the arc intersected by a central angle of $\frac{pi}{2}$ radians in a circle with a radius of…

how long is the arc intersected by a central angle of $\frac{pi}{2}$ radians in a circle with a radius of 4.5 cm? round your answer to the nearest tenth. use 3.14 for $pi$.\n0.3 cm\n0.7 cm\n2.9 cm\n7.1 cm
Answer
Explanation:
Step1: Recall arc - length formula
The formula for the length of an arc $s$ of a circle is $s = r\theta$, where $r$ is the radius of the circle and $\theta$ is the central angle in radians.
Step2: Substitute given values
We are given that $r = 4.5$ cm and $\theta=\frac{\pi}{2}$ radians. Substituting these values into the formula, we get $s=4.5\times\frac{\pi}{2}$.
Step3: Approximate $\pi$ and calculate
Using $\pi = 3.14$, we have $s = 4.5\times\frac{3.14}{2}=\frac{4.5\times3.14}{2}=\frac{14.13}{2}=7.065$ cm.
Step4: Round to the nearest tenth
Rounding $7.065$ to the nearest tenth gives $7.1$ cm.
Answer:
D. $7.1$ cm