how many solutions does the equation 6z + 1 = 2(3z - 1) have?\nno solution\none solution\ninfinitely many…
how many solutions does the equation 6z + 1 = 2(3z - 1) have?\nno solution\none solution\ninfinitely many solutions
Answer
Explanation:
Step1: Expand the right - hand side
Expand $2(3z - 1)$ using the distributive property $a(b - c)=ab - ac$. So $2(3z - 1)=6z-2$. The equation becomes $6z + 1=6z - 2$.
Step2: Subtract $6z$ from both sides
Subtracting $6z$ from both sides of the equation $6z + 1=6z - 2$, we get $(6z-6z)+1=(6z - 6z)-2$, which simplifies to $1=-2$.
Answer:
no solution