how many solutions exist for the given equation? 3(x + 10) + 6 = 3(x + 12) zero one two infinitely many
how many solutions exist for the given equation? 3(x + 10) + 6 = 3(x + 12) zero one two infinitely many
Answer
Explanation:
Step1: Expand both sides
Expand $3(x + 10)+6$ to get $3x+30 + 6=3x + 36$, and expand $3(x + 12)$ to get $3x+36$. So the equation becomes $3x+36=3x + 36$.
Step2: Analyze the equation
Subtract $3x$ from both sides of the equation $3x+36=3x + 36$. We get $36=36$. This is a true - statement for all real values of $x$.
Answer:
infinitely many