how many solutions exist for the given equation?\n3(x + 10) + 6 = 3(x + 12)\nzero\none\ntwo\ninfinitely many
how many solutions exist for the given equation?\n3(x + 10) + 6 = 3(x + 12)\nzero\none\ntwo\ninfinitely many
Answer
Explanation:
Step1: Expand both sides
$$ \begin{align*} 3(x + 10)+6&=3(x + 12)\ 3x+30 + 6&=3x+36\ 3x+36&=3x+36 \end{align*} $$
Step2: Analyze the equation
Subtract (3x) from both sides: (36 = 36). This is a True statement for all values of (x).
Answer:
infinitely many