how many solutions exist for the given equation? 12x + 1 = 3(4x + 1) - 2\nzero\none\ntwo\ninfinitely many
how many solutions exist for the given equation? 12x + 1 = 3(4x + 1) - 2\nzero\none\ntwo\ninfinitely many
Answer
Explanation:
Step1: Expand the right - hand side
Expand $3(4x + 1)-2$ using the distributive property $a(b + c)=ab+ac$. So $3(4x + 1)-2=12x+3 - 2=12x + 1$.
Step2: Compare both sides
The original equation is $12x + 1=3(4x + 1)-2$. After expanding the right - hand side, we get $12x + 1=12x + 1$. This is an identity, which means it is true for all values of $x$.
Answer:
infinitely many