how many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1 zero one two infinitely many
how many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1 zero one two infinitely many
Answer
Explanation:
Step1: Expand the right - hand side
Expand $3(x + 6)+1$ using the distributive property $a(b + c)=ab+ac$. So $3(x + 6)+1=3x+18 + 1=3x+19$. The original equation $3x + 13=3(x + 6)+1$ becomes $3x + 13=3x+19$.
Step2: Subtract $3x$ from both sides
Subtract $3x$ from both sides of the equation $3x + 13=3x+19$. $(3x-3x)+13=(3x - 3x)+19$. We get $13 = 19$, which is a false statement.
Answer:
zero