how many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1\nzero\none\ntwo\ninfinitely many

Answer:

A. zero

Explanation:

Step1: Expand the right - hand side

$3(x + 6)+1=3x+18 + 1=3x+19$

Step2: Rewrite the original equation

The original equation $3x + 13=3(x + 6)+1$ becomes $3x + 13=3x+19$.

Step3: Subtract $3x$ from both sides

$3x-3x + 13=3x-3x+19$, which simplifies to $13 = 19$. This is a false statement. So, the equation has zero solutions.