how many solutions exist for the given equation?\n3x + 13 = 3(x + 6) + 1\nzero\none\ntwo\ninfinitely many

Explanation:

Step1: Expand the right - hand side

Expand (3(x + 6)+1) using the distributive property (a(b + c)=ab+ac). So, (3(x + 6)+1=3x+18 + 1=3x+19). The equation becomes (3x + 13=3x+19).

Step2: Subtract (3x) from both sides

Subtract (3x) from both sides of the equation (3x + 13=3x+19). ((3x-3x)+13=(3x - 3x)+19). We get (13 = 19), which is a false statement.

Answer:

zero