how many solutions exist for the given equation? 0.75(x + 40) = 0.35(x + 20) + 0.35(x + 20)\nzero\none\ntwo\n…
how many solutions exist for the given equation? 0.75(x + 40) = 0.35(x + 20) + 0.35(x + 20)\nzero\none\ntwo\ninfinitely many
Answer
Explanation:
Step1: Expand both sides
$0.75x + 0.75\times40=0.35x+0.35\times20 + 0.35x+0.35\times20$ $0.75x + 30 = 0.7x+14$
Step2: Move like - terms to one side
$0.75x-0.7x=14 - 30$ $0.05x=-16$
Step3: Solve for x
$x=\frac{-16}{0.05}=-320$
Answer:
B. one