how many solutions exist for the given equation? 0.75(x + 40)=0.35(x + 20)+0.35(x + 20)\nzero\none\ntwo\ninfi…
how many solutions exist for the given equation? 0.75(x + 40)=0.35(x + 20)+0.35(x + 20)\nzero\none\ntwo\ninfinitely many
Answer
Explanation:
Step1: Expand both sides
$0.75x + 30=0.35x + 7+0.35x + 7$
Step2: Combine like - terms on the right - hand side
$0.75x + 30=(0.35x+0.35x)+(7 + 7)$ $0.75x + 30 = 0.7x+14$
Step3: Subtract $0.7x$ from both sides
$0.75x-0.7x + 30=0.7x-0.7x + 14$ $0.05x+30 = 14$
Step4: Subtract 30 from both sides
$0.05x+30 - 30=14 - 30$ $0.05x=-16$
Step5: Solve for $x$
$x=\frac{-16}{0.05}=-320$
Answer:
one