how many solutions does the system of equations below have?\n10x - 3y = -3\n20x - 6y = -6\nno solution\none…
how many solutions does the system of equations below have?\n10x - 3y = -3\n20x - 6y = -6\nno solution\none solution\ninfinitely many solutions
Answer
Explanation:
Step1: Simplify the second equation
Divide the second equation (20x - 6y=-6) by (2). $$\frac{20x - 6y}{2}=\frac{-6}{2}$$ We get (10x - 3y=-3), which is the same as the first equation.
Answer:
infinitely many solutions