how many values of x must be excluded in the expression $\frac{x - 2}{(x + 9)(x - 5)}$?\n0\n1\n2\n3
how many values of x must be excluded in the expression $\frac{x - 2}{(x + 9)(x - 5)}$?\n0\n1\n2\n3
Answer
Answer:
C. 2
Explanation:
Step1: Identify non - zero denominator condition
For a rational expression $\frac{a}{b}$, $b\neq0$. Here, $b=(x + 9)(x - 5)$.
Step2: Solve for excluded values
Set $(x + 9)(x - 5)=0$. Using the zero - product property, if $ab = 0$, then $a = 0$ or $b = 0$. So $x+9 = 0$ gives $x=-9$ and $x - 5=0$ gives $x = 5$. There are 2 values to be excluded.