how many ways can a history teacher choose 5 questions from a list of 8 study questions to be on the next…

how many ways can a history teacher choose 5 questions from a list of 8 study questions to be on the next test?

how many ways can a history teacher choose 5 questions from a list of 8 study questions to be on the next test?

Answer

Answer:

56

Explanation:

Step1: Identify combination formula

The formula for combinations is $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n$ is the total number of items, and $r$ is the number of items to be chosen.

Step2: Substitute values

Here, $n = 8$ and $r=5$. So $C(8,5)=\frac{8!}{5!(8 - 5)!}=\frac{8!}{5!3!}$.

Step3: Expand factorials

$8! = 8\times7\times6\times5!$, $3! = 3\times2\times1$. Then $C(8,5)=\frac{8\times7\times6\times5!}{5!\times3\times2\times1}$.

Step4: Simplify

The $5!$ terms cancel out. We have $\frac{8\times7\times6}{3\times2\times1}=\frac{336}{6}=56$.