marta is solving the equation $s = 2pi rh+2pi r^{2}$ for $h$. which should be the result?\n$\frac{s}{2pi…

marta is solving the equation $s = 2pi rh+2pi r^{2}$ for $h$. which should be the result?\n$\frac{s}{2pi r}-r = h$\n$\frac{s - r}{2pi r}=h$\n$s-\frac{r}{2pi}=h$\n$s-\frac{2pi}{r}=h$

marta is solving the equation $s = 2pi rh+2pi r^{2}$ for $h$. which should be the result?\n$\frac{s}{2pi r}-r = h$\n$\frac{s - r}{2pi r}=h$\n$s-\frac{r}{2pi}=h$\n$s-\frac{2pi}{r}=h$

Answer

Answer:

A. $\frac{S}{2\pi r}-r = h$

Explanation:

Step1: Isolate the term with h

$S = 2\pi rh+2\pi r^{2}$ $S - 2\pi r^{2}=2\pi rh$

Step2: Solve for h

Divide both sides by $2\pi r$: $\frac{S - 2\pi r^{2}}{2\pi r}=h$ Simplify the left - hand side: $\frac{S}{2\pi r}-\frac{2\pi r^{2}}{2\pi r}=h$ So, $\frac{S}{2\pi r}-r = h$