the math team wraps gifts as a way to raise money for traveling to competitions. they offer two choices: a…

the math team wraps gifts as a way to raise money for traveling to competitions. they offer two choices: a plain wrapping or a decorative wrapping with bows. the table represents the money raised over a busy shopping weekend.\ngift - wrapping fundraiser\n| plain gifts wrapped | decorative gifts wrapped | total raised ($) |\n| ---- | ---- | ---- |\n| 10 | 9 | 47 |\n| 25 | 12 | 86 |\n| 16 | 12 | 68 |\nwhich statement describes the amounts the team charged for wrapping gifts?\no the team charged $1 to wrap a gift with no bow and $2 to wrap a gift with a bow.\no the team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow.\no the team charged $3 to wrap a gift with no bow and $4 to wrap a gift with a bow.\no the team charged $4 to wrap a gift with no bow and $5 to wrap a gift with a bow.

the math team wraps gifts as a way to raise money for traveling to competitions. they offer two choices: a plain wrapping or a decorative wrapping with bows. the table represents the money raised over a busy shopping weekend.\ngift - wrapping fundraiser\n| plain gifts wrapped | decorative gifts wrapped | total raised ($) |\n| ---- | ---- | ---- |\n| 10 | 9 | 47 |\n| 25 | 12 | 86 |\n| 16 | 12 | 68 |\nwhich statement describes the amounts the team charged for wrapping gifts?\no the team charged $1 to wrap a gift with no bow and $2 to wrap a gift with a bow.\no the team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow.\no the team charged $3 to wrap a gift with no bow and $4 to wrap a gift with a bow.\no the team charged $4 to wrap a gift with no bow and $5 to wrap a gift with a bow.

Answer

Explanation:

Step1: Let cost of plain wrap be $x$ and decorative wrap be $y$.

Set up equations from table. For first - row: $10x + 9y=47$. For second - row: $25x + 12y = 86$.

Step2: Multiply first equation by 4 and second by 3 to make $y$ coefficients equal.

First equation becomes $40x+36y = 188$. Second equation becomes $75x+36y=258$.

Step3: Subtract the first new - equation from the second new - equation.

$(75x + 36y)-(40x + 36y)=258 - 188$. Simplify to get $35x=70$, so $x = 2$.

Step4: Substitute $x = 2$ into the first original equation.

$10\times2+9y=47$, which is $20 + 9y=47$. Then $9y=47 - 20=27$, so $y = 3$.

Answer:

The team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow.