mathias found the product $\frac{4x + 8}{x}cdot\frac{5}{x + 2}$ as follows. $\frac{4x + 8}{x}cdot\frac{5}{x…

mathias found the product $\frac{4x + 8}{x}cdot\frac{5}{x + 2}$ as follows. $\frac{4x + 8}{x}cdot\frac{5}{x + 2}=\frac{4x+8}{x}cdot\frac{5}{x + 2}=\frac{12}{1}cdot\frac{5}{x + 2}=\frac{60}{x + 2}$ which of the following best describes his error? he did not multiply the denominators correctly. he did not factor the first numerator. he did not divide out the 2 from the 4 and the 8. he did not distribute the 5 to the terms in the other numerator. done

mathias found the product $\frac{4x + 8}{x}cdot\frac{5}{x + 2}$ as follows. $\frac{4x + 8}{x}cdot\frac{5}{x + 2}=\frac{4x+8}{x}cdot\frac{5}{x + 2}=\frac{12}{1}cdot\frac{5}{x + 2}=\frac{60}{x + 2}$ which of the following best describes his error? he did not multiply the denominators correctly. he did not factor the first numerator. he did not divide out the 2 from the 4 and the 8. he did not distribute the 5 to the terms in the other numerator. done

Answer

Brief Explanations:

The correct way to simplify $\frac{4x + 8}{x}\cdot\frac{5}{x + 2}$ is to first factor $4x+8$ as $4(x + 2)$. Then we have $\frac{4(x + 2)}{x}\cdot\frac{5}{x + 2}$, and we can cancel out the $(x + 2)$ terms. Mathias did not factor the first - numerator $4x + 8$ before multiplying.

Answer:

He did not factor the first numerator.