at what meter mark will ario be when miguel starts the race? round to the nearest tenth.\n$x =…

at what meter mark will ario be when miguel starts the race? round to the nearest tenth.\n$x = \\left(\\frac{m}{m + n}\\right)(x_2 - x_1)+x_1$\nmiguel and his brother ario are both standing 3 meters from one side of a 25 - meter pool when they decide to race. miguel offers ario a head start. miguel says he will start when the ratio of arios completed meters to arios remaining meters is 1:4.\n4.4 meters\n7.4 meters\n17.6 meters\n20.6 meters

at what meter mark will ario be when miguel starts the race? round to the nearest tenth.\n$x = \\left(\\frac{m}{m + n}\\right)(x_2 - x_1)+x_1$\nmiguel and his brother ario are both standing 3 meters from one side of a 25 - meter pool when they decide to race. miguel offers ario a head start. miguel says he will start when the ratio of arios completed meters to arios remaining meters is 1:4.\n4.4 meters\n7.4 meters\n17.6 meters\n20.6 meters

Answer

Answer:

B. 7.4 meters

Explanation:

Step1: Identify the values

The pool is 25 - meter long, and they start 3 meters from one - side. So the total distance of the race for Ario is $d = 25 - 3=22$ meters. The ratio of Ario's completed meters to remaining meters is $m:n = 1:4$. Let $x_1 = 3$ (starting point), $x_2=25$, $m = 1$, $n = 4$.

Step2: Substitute into the formula

We use the formula $x=\left(\frac{m}{m + n}\right)(x_2 - x_1)+x_1$. Substitute $m = 1$, $n = 4$, $x_1 = 3$, and $x_2 = 25$ into the formula: First, calculate $\frac{m}{m + n}=\frac{1}{1 + 4}=\frac{1}{5}=0.2$. Then, calculate $x_2 - x_1=25 - 3 = 22$. Next, $\left(\frac{m}{m + n}\right)(x_2 - x_1)=0.2\times22 = 4.4$. Finally, $x=4.4+3=7.4$ meters.