what is the midpoint of the x - intercepts of f(x)=(x - 2)(x - 4)?\n(-3,0)\n(-1,0)\n(1,0)\n(3,0)
what is the midpoint of the x - intercepts of f(x)=(x - 2)(x - 4)?\n(-3,0)\n(-1,0)\n(1,0)\n(3,0)
Answer
Explanation:
Step1: Find x - intercepts
Set $f(x)=0$, so $(x - 2)(x - 4)=0$. Then $x-2 = 0$ or $x - 4=0$, which gives $x=2$ and $x = 4$.
Step2: Calculate mid - point of x - values
The formula for the mid - point of two numbers $a$ and $b$ is $\frac{a + b}{2}$. Here $a = 2$ and $b=4$, so $\frac{2+4}{2}=\frac{6}{2}=3$. The y - coordinate of the x - intercepts mid - point is 0. So the mid - point is $(3,0)$.
Answer:
D. $(3,0)$