the minimum of a parabola is located at (-1, -3). the point (0, 1) is also on the graph. which equation can…

the minimum of a parabola is located at (-1, -3). the point (0, 1) is also on the graph. which equation can be solved to determine the a value in the function representing the parabola?\n1 = a(0 + 1)^2 - 3\n1 = a(0 - 1)^2 + 3\n0 = a(1 + 1)^2 - 3\n0 = a(1 - 1)^2 + 3

the minimum of a parabola is located at (-1, -3). the point (0, 1) is also on the graph. which equation can be solved to determine the a value in the function representing the parabola?\n1 = a(0 + 1)^2 - 3\n1 = a(0 - 1)^2 + 3\n0 = a(1 + 1)^2 - 3\n0 = a(1 - 1)^2 + 3

Answer

Explanation:

Step1: Recall vertex - form of parabola

The vertex - form of a parabola is $y=a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola. Given the vertex is $(-1,-3)$, so $h=-1$ and $k = - 3$. Then the equation of the parabola is $y=a(x+1)^2 - 3$.

Step2: Substitute the point $(0,1)$

We know the point $(x = 0,y = 1)$ lies on the parabola. Substitute $x = 0$ and $y = 1$ into the equation $y=a(x + 1)^2-3$. We get $1=a(0 + 1)^2-3$.

Answer:

A. $1=a(0 + 1)^2-3$