mira picked two numbers from a bowl. the difference of the two numbers was 4, and the sum of one - half of…

mira picked two numbers from a bowl. the difference of the two numbers was 4, and the sum of one - half of each number was 18. the system that represents miras numbers is below.\n$x - y = 4$\n$\\frac{1}{2}x+\\frac{1}{2}y = 18$\nwhich two numbers did mira pick?\n10 and 8\n18 and 4\n20 and 16\n40 and 32

mira picked two numbers from a bowl. the difference of the two numbers was 4, and the sum of one - half of each number was 18. the system that represents miras numbers is below.\n$x - y = 4$\n$\\frac{1}{2}x+\\frac{1}{2}y = 18$\nwhich two numbers did mira pick?\n10 and 8\n18 and 4\n20 and 16\n40 and 32

Answer

Answer:

C. 20 and 16

Explanation:

Step1: Simplify the second - equation

Multiply $\frac{1}{2}x+\frac{1}{2}y = 18$ by 2. We get $x + y=36$.

Step2: Add the two equations

Add $x - y = 4$ and $x + y=36$. $(x - y)+(x + y)=4 + 36$ $2x=40$ $x = 20$

Step3: Find the value of y

Substitute $x = 20$ into $x - y = 4$. $20-y=4$ $y=20 - 4=16$ So the two numbers are 20 and 16.