miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her…

miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. the area of the reduced photo is 64 square inches. in the equation $(x - 3)^2=64$, $x$ represents the side measure of the original photo. what were the dimensions of the original photo? 11 inches by 11 inches 5 inches by 5 inches $3 + 4\\sqrt{2}$ inches by $3 + 4\\sqrt{2}$ inches $3 - 4\\sqrt{2}$ inches by $3 - 4\\sqrt{2}$ inches

miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. the area of the reduced photo is 64 square inches. in the equation $(x - 3)^2=64$, $x$ represents the side measure of the original photo. what were the dimensions of the original photo? 11 inches by 11 inches 5 inches by 5 inches $3 + 4\\sqrt{2}$ inches by $3 + 4\\sqrt{2}$ inches $3 - 4\\sqrt{2}$ inches by $3 - 4\\sqrt{2}$ inches

Answer

Explanation:

Step1: Resolver la ecuación $(x - 3)^2=64$.

Tomar la raíz cuadrada de ambos lados: $x - 3=\pm\sqrt{64}$, es decir $x - 3=\pm8$.

Step2: Resolver para $x$ en los dos casos.

Caso 1: $x - 3 = 8$, entonces $x=8 + 3=11$. Caso 2: $x - 3=-8$, entonces $x=-8 + 3=-5$. Pero las dimensiones no pueden ser negativas, así que descartamos esta solución.

Answer:

11 inches by 11 inches