mr. hernandez plotted the point (1, 1) on hans graph of $yleq\frac{1}{2}x + 2$. he instructed han to add a…

mr. hernandez plotted the point (1, 1) on hans graph of $yleq\frac{1}{2}x + 2$. he instructed han to add a second inequality to the graph that would include the solution (1, 1). which equation could miguel write?\n$y>2x + 1$\n$y<2x - 1$\n$ygeq2x + 1$\n$yleq2x - 1$

mr. hernandez plotted the point (1, 1) on hans graph of $yleq\frac{1}{2}x + 2$. he instructed han to add a second inequality to the graph that would include the solution (1, 1). which equation could miguel write?\n$y>2x + 1$\n$y<2x - 1$\n$ygeq2x + 1$\n$yleq2x - 1$

Answer

Explanation:

Step1: Substitute the point (1,1) into each inequality.

For $y>2x + 1$, when $x = 1$ and $y=1$, we have $1>2\times1 + 1$, i.e., $1>3$ which is false. For $y<2x - 1$, when $x = 1$ and $y = 1$, we have $1<2\times1-1$, i.e., $1<1$ which is false. For $y\geq2x + 1$, when $x = 1$ and $y = 1$, we have $1\geq2\times1+1$, i.e., $1\geq3$ which is false. For $y\leq2x - 1$, when $x = 1$ and $y = 1$, we have $1\leq2\times1-1$, i.e., $1\leq1$ which is true.

Answer:

$y\leq2x - 1$