multiply.\n$(x^{4}+1)(3x^{2}+9x + 2)$\n$x^{4}+3x^{2}+9x + 3$\n$3x^{6}+9x^{5}+2x^{4}+3x^{2}+9x +…

multiply.\n$(x^{4}+1)(3x^{2}+9x + 2)$\n$x^{4}+3x^{2}+9x + 3$\n$3x^{6}+9x^{5}+2x^{4}+3x^{2}+9x + 2$\n$3x^{7}+9x^{6}+2x^{5}$\n$3x^{8}+9x^{4}+2x^{4}+3x^{2}+9x + 2$\ndone
Answer
Explanation:
Step1: Use distributive property
$(x^{4}+1)(3x^{2}+9x + 2)=x^{4}(3x^{2}+9x + 2)+1\times(3x^{2}+9x + 2)$
Step2: Multiply $x^{4}$ with each term
$x^{4}(3x^{2}+9x + 2)=3x^{4 + 2}+9x^{4+1}+2x^{4}=3x^{6}+9x^{5}+2x^{4}$
Step3: Multiply 1 with each term
$1\times(3x^{2}+9x + 2)=3x^{2}+9x + 2$
Step4: Combine results
$(3x^{6}+9x^{5}+2x^{4})+(3x^{2}+9x + 2)=3x^{6}+9x^{5}+2x^{4}+3x^{2}+9x + 2$
Answer:
B. $3x^{6}+9x^{5}+2x^{4}+3x^{2}+9x + 2$