multiply the complex numbers (4 - 6i) and (8 - 5i).\na 2 + 68i\nb 2 - 68i\nc 62 - 28i\nd 62 + 28i

multiply the complex numbers (4 - 6i) and (8 - 5i).\na 2 + 68i\nb 2 - 68i\nc 62 - 28i\nd 62 + 28i
Answer
Explanation:
Step1: Use the FOIL method
$$(4 - 6i)(8 - 5i)=4\times8+4\times(- 5i)-6i\times8+(-6i)\times(-5i)$$
Step2: Calculate each term
- Calculate (4\times8 = 32)
- Calculate (4\times(-5i)=-20i)
- Calculate (-6i\times8=-48i)
- Calculate ((-6i)\times(-5i)=30i^{2})
Since (i^{2}=-1), then (30i^{2}=-30)
Step3: Combine like - terms
[ \begin{align*} &32-20i - 48i-30\ =&(32 - 30)+(-20i-48i)\ =&2-68i \end{align*} ]
Answer:
B. (2 - 68i)