nathaniel writes the general form of the equation $gm = cm+rg$ for when the equation is solved for $m$. he…

nathaniel writes the general form of the equation $gm = cm+rg$ for when the equation is solved for $m$. he uses the general form to solve the equation $-3m = 4m - 15$ for $m$. which expression shows what nathaniel will actually evaluate?\n$4 + 15-3$\n$4 - 15 + 3$\n$\frac{-15}{-3 - 4}$\n$-15-\frac{-3}{4}$

nathaniel writes the general form of the equation $gm = cm+rg$ for when the equation is solved for $m$. he uses the general form to solve the equation $-3m = 4m - 15$ for $m$. which expression shows what nathaniel will actually evaluate?\n$4 + 15-3$\n$4 - 15 + 3$\n$\frac{-15}{-3 - 4}$\n$-15-\frac{-3}{4}$

Answer

Explanation:

Step1: Rearrange the general equation $gm = cm+rg$ for $m$.

Subtract $cm$ from both sides: $gm - cm=rg$. Factor out $m$ on the left - hand side: $m(g - c)=rg$. Then $m=\frac{rg}{g - c}$.

Step2: Match the given equation $-3m = 4m-15$ to the general form.

Rewrite $-3m = 4m - 15$ as $(-3)m=4m+(- 15)$. Here, $g=-3$, $c = 4$, and $rg=-15$. Substitute into the formula $m=\frac{rg}{g - c}$, we get $m=\frac{-15}{-3 - 4}$.

Answer:

$\frac{-15}{-3 - 4}$