what is the net ionic equation of $\\ce{na+ + oh- + h+ + cl- -> h2o + na+ + cl-}$?\na. $\\ce{na+ + cl- ->…

what is the net ionic equation of $\\ce{na+ + oh- + h+ + cl- -> h2o + na+ + cl-}$?\na. $\\ce{na+ + cl- -> nacl}$\nb. $\\ce{naoh(aq) + hcl(aq) -> h2o(l) + nacl(aq)}$\nc. $\\ce{oh- + h+ -> h2o}$\nd. $\\ce{na+ + oh- + h+ + cl- -> h+ + oh- + na+ + cl-}$

what is the net ionic equation of $\\ce{na+ + oh- + h+ + cl- -> h2o + na+ + cl-}$?\na. $\\ce{na+ + cl- -> nacl}$\nb. $\\ce{naoh(aq) + hcl(aq) -> h2o(l) + nacl(aq)}$\nc. $\\ce{oh- + h+ -> h2o}$\nd. $\\ce{na+ + oh- + h+ + cl- -> h+ + oh- + na+ + cl-}$

Answer

Answer:

C. OH⁻ + H⁺ → H₂O

Explanation:

Step1: Identify spectator ions

Spectator ions are unchanged on both sides: Na⁺ and Cl⁻.

Step2: Remove spectator ions

Cancel Na⁺ and Cl⁻ from reactants and products.

Step3: Write net ionic equation

Remaining ions: OH⁻ + H⁺ → H₂O.