new designs charter school ~ adams campus. end of semester on... riley jr., steven d. #11 review toolbox…

graph The graph is a line, so we can observe the coordinates. When ( x = 8 ), we look at the point on the line corresponding to ( x = 8 ). From the graph, we can see the pattern or directly read the ( y )-value. Looking at the grid, when ( x = 8 ), the ( y )-value is 4? Wait, no, let's check again. Wait, the line: let's see the slope. Wait, maybe it's a linear graph. Wait, when ( x = 0 ), ( y = 0 ). Let's check the points. At ( x = 4 ), ( y = 2 ); at ( x = 8 ), let's see. Wait, the graph: from ( x = 0 ) to ( x = 10 ), the line goes up. Wait, maybe the graph has a point at ( x = 8 ), ( y = 4 )? Wait, no, wait the grid. Wait, the ( y )-axis is from 0 to 10, ( x )-axis from 0 to 10. Let's see the line: when ( x = 8 ), the ( y )-coordinate is 4? Wait, no, maybe I made a mistake. Wait, let's look again. The graph: at ( x = 8 ), the vertical line from ( x = 8 ) meets the line at ( y = 4 )? Wait, no, maybe the slope is ( \frac{1}{2} )? Wait, no, let's check the points. At ( x = 2 ), ( y = 1 ); ( x = 4 ), ( y = 2 ); ( x = 6 ), ( y = 3 ); ( x = 8 ), ( y = 4 ); ( x = 10 ), ( y = 5 ). Oh, right, so the pattern is ( y=\frac{1}{2}x )? Wait, no, when ( x = 2 ), ( y = 1 ), so slope is ( \frac{1}{2} ). So when ( x = 8 ), ( y=\frac{1}{2}\times8 = 4 )? Wait, no, wait the graph: the line goes from (0,0) to (10,5)? Wait, no, the arrow is at (10,5)? Wait, the graph shows at ( x = 10 ), ( y = 5 ). So slope is ( \frac{5}{10}=\frac{1}{2} ). So equation is ( y = \frac{1}{2}x ). So when ( x = 8 ), ( y=\frac{1}{2}\times8 = 4 ). Wait, but looking at the graph, when ( x = 8 ), the ( y )-value is 4? Wait, no, maybe the graph has a vertical segment? Wait, no, the line is a straight line. Wait, the grid: each square is 1 unit. So at ( x = 8 ), the ( y )-coordinate is 4? Wait, no, maybe I misread. Wait, the graph: from (0,0) to (8,4)? Wait, the point at ( x = 8 ) is (8,4)? So ( y = 4 ) when ( x = 8 ).

Step2: Confirm the value

By observing the graph, when ( x = 8 ), the ( y )-value is 4. Or using the linear relationship: since the line passes through (0,0) and (10,5), the slope is ( \frac{5 - 0}{10 - 0}=\frac{1}{2} ), so the equation is ( y=\frac{1}{2}x ). Substituting ( x = 8 ), we get ( y=\frac{1}{2}\times8 = 4 ).

Answer:

( y = 4 )