what number would you add to both sides of $x^{2}+7x = 4$ to complete the square?\n$2^{2}$\n$7^{2}$\n$\frac{7…

what number would you add to both sides of $x^{2}+7x = 4$ to complete the square?\n$2^{2}$\n$7^{2}$\n$\frac{7^{2}}{2}$\n$(\frac{7}{2})^{2}$

what number would you add to both sides of $x^{2}+7x = 4$ to complete the square?\n$2^{2}$\n$7^{2}$\n$\frac{7^{2}}{2}$\n$(\frac{7}{2})^{2}$

Answer

Explanation:

Step1: Recall the formula for completing the square

For a quadratic equation of the form $x^{2}+bx = c$, to complete the square, we add $\left(\frac{b}{2}\right)^{2}$ to both sides.

Step2: Identify the value of b

In the equation $x^{2}+7x = 4$, the coefficient of $x$ is $b = 7$.

Step3: Calculate the number to add

We calculate $\left(\frac{b}{2}\right)^{2}$ with $b = 7$. So, $\left(\frac{7}{2}\right)^{2}$ should be added to both sides.

Answer:

D. $\left(\frac{7}{2}\right)^{2}$