one leg of an isosceles right triangle measures 5 inches. rounded to the nearest tenth, what is the…

Explanation:

Step1: Recall Pythagorean theorem

In a right - triangle, (a^{2}+b^{2}=c^{2}), where (c) is the hypotenuse and (a) and (b) are the legs. In an isosceles right - triangle, (a = b). Given (a=b = 5) inches.

Step2: Substitute values into the formula

Substitute (a = 5) and (b = 5) into (a^{2}+b^{2}=c^{2}), we get (5^{2}+5^{2}=c^{2}), which simplifies to (25 + 25=c^{2}), so (c^{2}=50).

Step3: Solve for (c)

Take the square root of both sides: (c=\sqrt{50}). Since (\sqrt{50}=\sqrt{25\times2}=5\sqrt{2}\approx5\times1.414 = 7.07).

Step4: Round to the nearest tenth

Rounding (7.07) to the nearest tenth gives (7.1).

Answer:

C. 7.1 inches