which ordered pair makes both inequalities true?\ny > -2x + 3\ny ≤ x - 2\n(0,0)\n(0,-1)\n(1,1)\n(3,0)

Explanation:

Step1: Test (0,0)

For $y > - 2x+3$, substitute $x = 0$ and $y = 0$: $0>-2\times0 + 3$ gives $0>3$ (false). For $y\leq x - 2$, substitute $x = 0$ and $y = 0$: $0\leq0 - 2$ gives $0\leq - 2$ (false).

Step2: Test (0,-1)

For $y > - 2x+3$, substitute $x = 0$ and $y=-1$: $-1>-2\times0 + 3$ gives $-1>3$ (false). For $y\leq x - 2$, substitute $x = 0$ and $y=-1$: $-1\leq0 - 2$ gives $-1\leq - 2$ (false).

Step3: Test (1,1)

For $y > - 2x+3$, substitute $x = 1$ and $y = 1$: $1>-2\times1+3$ gives $1>1$ (false). For $y\leq x - 2$, substitute $x = 1$ and $y = 1$: $1\leq1 - 2$ gives $1\leq - 1$ (false).

Step4: Test (3,0)

For $y > - 2x+3$, substitute $x = 3$ and $y = 0$: $0>-2\times3+3$ gives $0>-3$ (true). For $y\leq x - 2$, substitute $x = 3$ and $y = 0$: $0\leq3 - 2$ gives $0\leq1$ (true).

Answer:

D. (3,0)