which ordered pair makes both inequalities true?\ny > -3x + 3\ny ≥ 2x - 2\n(1,0)\n(-1,1)\n(2,2)\n(0,3)

which ordered pair makes both inequalities true?\ny > -3x + 3\ny ≥ 2x - 2\n(1,0)\n(-1,1)\n(2,2)\n(0,3)

which ordered pair makes both inequalities true?\ny > -3x + 3\ny ≥ 2x - 2\n(1,0)\n(-1,1)\n(2,2)\n(0,3)

Answer

Explanation:

Step1: Check for ((1,0))

For (y > - 3x + 3), substitute (x = 1,y = 0): (0>-3\times1 + 3), (0>0) (False)

Step2: Check for ((-1,1))

For (y > - 3x + 3), substitute (x=-1,y = 1): (1>-3\times(-1)+3), (1>6) (False)

Step3: Check for ((2,2))

For (y > - 3x + 3), substitute (x = 2,y = 2): (2>-3\times2+3), (2>-3) (True) For (y\geq2x - 2), substitute (x = 2,y = 2): (2\geq2\times2-2), (2\geq2) (True)

Step4: Check for ((0,3))

For (y\geq2x - 2), substitute (x = 0,y = 3): (3\geq2\times0-2), (3\geq - 2) (True) For (y > - 3x + 3), substitute (x = 0,y = 3): (3>-3\times0+3), (3>3) (False)

Answer:

((2,2))