which ordered pair makes both inequalities true?\ny > -3x + 3\ny ≥ 2x - 2

Explanation:

Step1: Recall the concept of solution of inequalities

The solution of a system of inequalities is the set of all ordered - pairs that satisfy both inequalities. We can test ordered - pairs by substituting the (x) and (y) values into the inequalities.

Step2: Let's assume an ordered - pair ((x,y)) and test it

Let's take an ordered - pair in the overlapping region of the two inequalities on the graph. For example, if we take (x = 2) and (y = 2). For the first inequality (y>-3x + 3), substitute (x = 2) and (y = 2): [2>-3\times2 + 3] [2>-6 + 3] [2>-3] (True) For the second inequality (y\geq2x-2), substitute (x = 2) and (y = 2): [2\geq2\times2-2] [2\geq4 - 2] [2\geq2] (True)

We can also note that the overlapping region of the two inequalities (y>-3x + 3) (a dashed line with slope (-3) and (y) - intercept (3)) and (y\geq2x-2) (a solid line with slope (2) and (y) - intercept (-2)) on the graph represents the set of all ordered - pairs that satisfy both inequalities.

Answer:

Any ordered pair ((x,y)) from the overlapping region of the two inequalities on the graph is a solution. For example, ((2,2)) is a solution.