which ordered pair (x, y) is the solution to the given system of linear equations?\\begin{cases}3x + 3y =…

which ordered pair (x, y) is the solution to the given system of linear equations?\\begin{cases}3x + 3y = -3\\\\-2x + y = 2\\end{cases}\\( -1, 0 )\\( 0, -1 )\\( 1, -2 )\\( 1, 4 )

which ordered pair (x, y) is the solution to the given system of linear equations?\\begin{cases}3x + 3y = -3\\\\-2x + y = 2\\end{cases}\\( -1, 0 )\\( 0, -1 )\\( 1, -2 )\\( 1, 4 )

Answer

Explanation:

Step1: Simplify the first equation

Divide the first equation (3x + 3y=-3) by 3, we get (x + y=-1), so (y=-1 - x).

Step2: Substitute into the second equation

Substitute (y=-1 - x) into the second equation (-2x + y = 2), we have (-2x+(-1 - x)=2). Simplify the left - hand side: (-2x-1 - x=2), combine like terms to get (-3x-1 = 2). Add 1 to both sides: (-3x=2 + 1=3). Divide both sides by - 3: (x=-1).

Step3: Find the value of y

Substitute (x = - 1) into (y=-1 - x), we get (y=-1-(-1)=0).

Answer:

((-1,0))