which ordered pair is a solution to the system of linear equations? 2x + 3y = 6 -3x + 5y = 10 (0,2) (2,0)…

Explanation:

Step1: Substitute (0,2) into equations

For $2x + 3y=6$, substitute $x = 0$ and $y = 2$: $2\times0+3\times2=6$, which is $0 + 6=6$ (true). For $-3x + 5y = 10$, substitute $x = 0$ and $y = 2$: $-3\times0+5\times2=10$, which is $0 + 10=10$ (true).

Step2: Substitute (2,0) into equations

For $2x + 3y=6$, substitute $x = 2$ and $y = 0$: $2\times2+3\times0=4\neq6$ (false).

Step3: Substitute (3,2) into equations

For $2x + 3y=6$, substitute $x = 3$ and $y = 2$: $2\times3+3\times2=6 + 6=12\neq6$ (false).

Step4: Substitute (2,3) into equations

For $2x + 3y=6$, substitute $x = 2$ and $y = 3$: $2\times2+3\times3=4 + 9=13\neq6$ (false).

Answer:

$(0,2)$