$\\overleftrightarrow{rt}$ is a perpendicular bisector of $\\overline{uv}$. what is true of any triangle…

$\\overleftrightarrow{rt}$ is a perpendicular bisector of $\\overline{uv}$. what is true of any triangle created by points u, v, and any point on $\\overleftrightarrow{rt}$ other than s? \\bigcirc it will be a right triangle. \\bigcirc it will be an acute triangle. \\bigcirc it will be an equilateral triangle. \\bigcirc it will be an isosceles triangle.
Answer
Explanation:
Step1: Recall perpendicular bisector property
Any point on the perpendicular bisector of a segment is equidistant from the segment's endpoints. So, for any point ( P ) on ( \overleftrightarrow{RT} ) (perpendicular bisector of ( \overline{UV} )), ( PU = PV ).
Step2: Define triangle type
A triangle with two equal sides is isosceles. Since ( PU = PV ), ( \triangle UPV ) has two equal sides.
Answer:
D. It will be an isosceles triangle.