pams eye - level height is 324 ft above sea level, and adams eye - level height is 400 ft above sea level…

pams eye - level height is 324 ft above sea level, and adams eye - level height is 400 ft above sea level. how much farther can adam see to the horizon? use the formula $d = sqrt{\frac{3h}{2}}$, with $d$ being the distance they can see in miles and $h$ being their eye - level height in feet.\n1 mi\n$sqrt{6}$ mi\n19 mi\n$19sqrt{6}$ mi

pams eye - level height is 324 ft above sea level, and adams eye - level height is 400 ft above sea level. how much farther can adam see to the horizon? use the formula $d = sqrt{\frac{3h}{2}}$, with $d$ being the distance they can see in miles and $h$ being their eye - level height in feet.\n1 mi\n$sqrt{6}$ mi\n19 mi\n$19sqrt{6}$ mi

Answer

Explanation:

Step1: Calculate Adam's viewing - distance

Given the formula $d = \sqrt{\frac{3h}{2}}$, and Adam's eye - level height $h_{Adam}=400$ ft. Substitute $h = 400$ into the formula: $d_{Adam}=\sqrt{\frac{3\times400}{2}}=\sqrt{600}=10\sqrt{6}$ miles.

Step2: Calculate Pam's viewing - distance

Pam's eye - level height $h_{Pam}=324$ ft. Substitute $h = 324$ into the formula: $d_{Pam}=\sqrt{\frac{3\times324}{2}}=\sqrt{486}=9\sqrt{6}$ miles.

Step3: Calculate the difference in viewing distances

Find the difference $\Delta d=d_{Adam}-d_{Pam}$. $\Delta d = 10\sqrt{6}-9\sqrt{6}=\sqrt{6}$ miles.

Answer:

$\sqrt{6}$ mi