in the parallelogram shown, ae = p - 8, ce = 2p - 58, and de = p + 15. what is the length of line segment…

in the parallelogram shown, ae = p - 8, ce = 2p - 58, and de = p + 15. what is the length of line segment eb? 42 units 50 units 65 units 73 units

in the parallelogram shown, ae = p - 8, ce = 2p - 58, and de = p + 15. what is the length of line segment eb? 42 units 50 units 65 units 73 units

Answer

Explanation:

Step1: Use parallelogram property

In a parallelogram, the diagonals bisect each other. So (AE = CE). Set up the equation (p - 8=2p - 58).

Step2: Solve for (p)

Subtract (p) from both sides: (- 8=p - 58). Then add 58 to both sides: (p=50).

Step3: Find (DE)

Substitute (p = 50) into the expression for (DE), (DE=p + 15). So (DE=50+15=65).

Step4: Use diagonal - bisecting property again

Since the diagonals of a parallelogram bisect each other, (DE = EB). So (EB = 65).

Answer:

65 units