2) a passenger plane made a trip to las vegas and back. on the trip there it flew 432 mph and on the return…

2) a passenger plane made a trip to las vegas and back. on the trip there it flew 432 mph and on the return trip it went 480 mph. how long did the trip there take if the return trip took nine hours?

2) a passenger plane made a trip to las vegas and back. on the trip there it flew 432 mph and on the return trip it went 480 mph. how long did the trip there take if the return trip took nine hours?

Answer

Explanation:

Step1: Find the distance of the return - trip

Since distance = speed×time, and the speed of the return - trip is 480 mph and the time is 9 hours. $d = 480\times9=4320$ miles

Step2: Find the time of the trip there

The speed of the trip there is 432 mph, and the distance is the same as the return - trip (4320 miles). Using the formula time = distance÷speed. $t=\frac{4320}{432}=10$ hours

Answer:

10 hours