perform the indicated operation.\n\n\\( \\frac { 3 x ^ { 2 } - 3 x - 18 } { 2 x ^ { 2 } + 8 x - 20 } \\div…

perform the indicated operation.\n\n\\( \\frac { 3 x ^ { 2 } - 3 x - 18 } { 2 x ^ { 2 } + 8 x - 20 } \\div \\frac { x ^ { 2 } - 5 x - 14 } { x ^ { 2 } - 8 x + 7 } \\)\n\n\\( \\frac { 3 x ^ { 2 } - 3 x - 18 } { 2 x ^ { 2 } + 8 x - 20 } \\div \\frac { x ^ { 2 } - 5 x - 14 } { x ^ { 2 } - 8 x + 7 } = \\square \\)\n(simplify your answer.)

perform the indicated operation.\n\n\\( \\frac { 3 x ^ { 2 } - 3 x - 18 } { 2 x ^ { 2 } + 8 x - 20 } \\div \\frac { x ^ { 2 } - 5 x - 14 } { x ^ { 2 } - 8 x + 7 } \\)\n\n\\( \\frac { 3 x ^ { 2 } - 3 x - 18 } { 2 x ^ { 2 } + 8 x - 20 } \\div \\frac { x ^ { 2 } - 5 x - 14 } { x ^ { 2 } - 8 x + 7 } = \\square \\)\n(simplify your answer.)

Answer

Explanation:

Step1: Factor the polynomials

  • Factor (3x^{2}-3x - 18): (3(x^{2}-x - 6)=3(x - 3)(x+2))
  • Factor (2x^{2}+8x - 20): (2(x^{2}+4x - 10)=2(x^{2}+4x - 10)) (Wait, no, (2x^{2}+8x - 20=2(x^{2}+4x - 10)) is wrong. Correctly: (2x^{2}+8x - 20 = 2(x^{2}+4x - 10)) is wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) no. (2x^{2}+8x - 20=2(x^{2}+4x - 10)) wrong. 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