perform the indicated operation and simplify the result so that there are no quotients. \n\\( \\frac { 1 } {…

perform the indicated operation and simplify the result so that there are no quotients. \n\\( \\frac { 1 } { \\csc ^ { 2 } \\theta } + \\frac { 1 } { \\sec ^ { 2 } \\theta } \\)\n\\( \\frac { 1 } { \\csc ^ { 2 } \\theta } + \\frac { 1 } { \\sec ^ { 2 } \\theta } = \\square \\) (simplify your answer.)
Answer
Explanation:
Step1: Use reciprocal identities
Recall that (\csc\theta=\frac{1}{\sin\theta}), so (\frac{1}{\csc^{2}\theta}=\sin^{2}\theta); and (\sec\theta = \frac{1}{\cos\theta}), so (\frac{1}{\sec^{2}\theta}=\cos^{2}\theta). $$\frac{1}{\csc^{2}\theta}+\frac{1}{\sec^{2}\theta}=\sin^{2}\theta+\cos^{2}\theta$$
Step2: Use Pythagorean identity
By the Pythagorean identity (\sin^{2}\theta+\cos^{2}\theta = 1)
Answer:
(1)