plan b\n* $40 per month buys 200 minutes.\n* additional time costs $0.30 per minute.\n$c(t)=\begin{cases}40&…

plan b\n* $40 per month buys 200 minutes.\n* additional time costs $0.30 per minute.\n$c(t)=\begin{cases}40& \text{if }0leq tleq200\\40 + 0.30(t - 200)&\text{if }t>200end{cases}$\n95. simplify the algebraic expression in the second - line piecewise function for plan a. then use point - plotting to graph the function.\n96. simplify the algebraic expression in the second - line piecewise function for plan b. then use point - plotting to graph the function.

plan b\n* $40 per month buys 200 minutes.\n* additional time costs $0.30 per minute.\n$c(t)=\begin{cases}40& \text{if }0leq tleq200\\40 + 0.30(t - 200)&\text{if }t>200end{cases}$\n95. simplify the algebraic expression in the second - line piecewise function for plan a. then use point - plotting to graph the function.\n96. simplify the algebraic expression in the second - line piecewise function for plan b. then use point - plotting to graph the function.

Answer

Explanation:

Step1: Simplify for Plan A

For (t[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]