which point corresponds to the real zero of the graph of $y = \\log_3(x + 2)-1$?\n(-1,-1)\n(1,0)\n(-1,0)\n(0…
which point corresponds to the real zero of the graph of $y = \\log_3(x + 2)-1$?\n(-1,-1)\n(1,0)\n(-1,0)\n(0,-.369)
Answer
Explanation:
Step1: Set y equal to 0
Set $\log_3(x + 2)-1=0$.
Step2: Isolate the logarithmic term
Add 1 to both sides: $\log_3(x + 2)=1$.
Step3: Convert to exponential form
By the definition of logarithms, if $\log_a b=c$, then $a^c = b$. So $3^1=x + 2$.
Step4: Solve for x
$x=3 - 2=1$. When $x = 1$, $y = 0$.
Answer:
(1,0)