which point is an x - intercept of the quadratic function $f(x)=(x - 8)(x + 9)$?\n(0,8)\n(0…

which point is an x - intercept of the quadratic function $f(x)=(x - 8)(x + 9)$?\n(0,8)\n(0, - 8)\n(9,0)\n(-9,0)

which point is an x - intercept of the quadratic function $f(x)=(x - 8)(x + 9)$?\n(0,8)\n(0, - 8)\n(9,0)\n(-9,0)

Answer

Explanation:

Step1: Recall x - intercept definition

The x - intercepts of a function (y = f(x)) occur when (y = 0), i.e., (f(x)=0). Set ((x - 8)(x + 9)=0).

Step2: Apply zero - product property

If (ab = 0), then either (a = 0) or (b = 0). So, (x-8=0) gives (x = 8) and (x + 9=0) gives (x=-9). The x - intercepts are of the form ((x,0)). So the x - intercepts are ((8,0)) and ((-9,0)).

Answer:

D. ((-9,0))